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real numbers
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real numbersHCF of (65,117) is 13 then express it in the form 65m+117n where m and n are integers?
Re: real numbersthe answer is m=2 and n=-1
this came in the int maths olympiad
Re: real numbersthe best thing u can do is ask ur teacher.
Re: real numbers117=65 * 1 + 52 --------(1)
65=52 * 1 + 13 -----(2) 52=13 * 4 + 0 -----(3 ) So HCF=13 now, 13= 65 - ( 52 * 1) {from (2)} but 52= 117 - (65 * 1) {from(1)} so 13 = 65 - { 117 - (65*1)} 13= 65 -117 + 65 13 = {65 * 2} + {117 * (-1)} where m=2 and n= -1 SO in which school do u study
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