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Trigonometry Question
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Trigonometry QuestionAt the foot of a mountain, the elevation of its summit is 45. After ascending 1 km towards the mountain up an incline of 30, the elevation changes to 60. Find the height of the mountain.
Re: Trigonometry Questiongiven:- /_acb=45 /__ocb=30 /___aoe=60 oc=1 km required to find= Height=AE proof:-- od/oc= sin30=1/2 oc=1 Km thus, od=1/2 km od=eb=1/2 km dc/oc=cos 30 = root3 /2 oc= 1 Km thus dc= root 3 /2 let oe=x km oe=db=x km ae/oe =tan 60=root3 ae/x=root3 thus ae=root 3 x ab/bc=tan 45 thus ab=bc ab=ae+eb= root3x + 1/2 bc=bd+dc=x +root3/2 thus root3x + 1/2 = x +root3/2 [2root3x + 1]/2 =[2x +root3]/2 2root3x + 1=2x +root3 2root3x -2x=root3-1 2x (root3-1)=root3-1 2x=1 x=1/2 now height=ab=ae+eb=root3x+1/2 =root3/2 + 1/2 =[root3 +1]/2 approx=1.366 Km thats it hope its not confusin dunno how to type angle or root lolz
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