how to solve this: http://techrecipe.blogspot.com/2008/06/test.html
Here DL&BM are angle bisectors
and we have to prove that <BMC+<ALD= 1/2 (<ADC+<ABC>)
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Maths Problem
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Maths Problemhow to solve this: http://techrecipe.blogspot.com/2008/06/test.html
Here DL&BM are angle bisectors and we have to prove that <BMC+<ALD= 1/2 (<ADC+<ABC>)
Re: Maths ProblemHello Siddharth,
Please find the answer for your question. In Parallelogram ABCD, AB II DC AL II MC (Extensions of AB and DC Rescpectively) Ang ABM = Ang BMC (Alternate Angles) (1) Ang ALD= Ang LDC ( Alternate Angles) (2) Ang ABM = 1/2 Ang ABC ( Given BM is angle bisector of ang ABC) Ang LDC = 1/2 Ang ADC ( Given DL is angle bisector of ang ADC) Ang ABM+LDC = 1/2(Ang ABC+Ang ADC) (3) But Ang ABM = Ang BMC & Ang LDC =ALD ( from 1 & 2) Therefore Ang BMC+ Ang ALD= 1/2(Ang ABC+ Ang ADC) ( from 1, 2 & 3) Thanks & Regards, Poornima.
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