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Maths Problem

Ask questions of CBSE Class IX and discuss the same here. For any doubts relates to CBSE Class IX.

Maths Problem

Postby siddhartha_dutta » Tue Jun 17, 2008 2:35 pm

how to solve this: http://techrecipe.blogspot.com/2008/06/test.html

Here DL&BM are angle bisectors
and we have to prove that <BMC+<ALD= 1/2 (<ADC+<ABC>)
siddhartha_dutta
 
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Re: Maths Problem

Postby shubham » Sun Aug 31, 2008 7:57 pm

some easy ways to solve problems :lol:
shubham
 
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Joined: Sat Jul 26, 2008 1:52 pm

Re: Maths Problem

Postby pspoornima » Fri May 15, 2009 8:49 am

Hello Siddharth,

Please find the answer for your question.

In Parallelogram ABCD,

AB II DC
AL II MC (Extensions of AB and DC Rescpectively)

Ang ABM = Ang BMC (Alternate Angles) (1)
Ang ALD= Ang LDC ( Alternate Angles) (2)


Ang ABM = 1/2 Ang ABC ( Given BM is angle bisector of ang ABC)
Ang LDC = 1/2 Ang ADC ( Given DL is angle bisector of ang ADC)

Ang ABM+LDC = 1/2(Ang ABC+Ang ADC) (3)

But Ang ABM = Ang BMC & Ang LDC =ALD ( from 1 & 2)

Therefore
Ang BMC+ Ang ALD= 1/2(Ang ABC+ Ang ADC) ( from 1, 2 & 3)

Thanks & Regards,
Poornima.
pspoornima
 
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