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Physics - Impulse
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Physics - ImpulseA glass marble, whose mass is 100g, falls from a height of 40m and rebounds to a height of 10m. Find the impulse and the average force between the marble and the floor, if the time during which they are in contact is 0.2s
Regards,
bcappu
Re: Physics - ImpulseImpulse=mv-mu
v1=(2*9.8*40)^.5 =28 m/s Similarly, u(velocity after bouncing)=-14m/s impulse=-1.4-2.8=-4.2Ns force=I/t=-4.2/0.2=-2.1N razr[img height="60" width="60"]http://farm1.static.flickr.com/143/3737 ... 69.jpg?v=0[/img]
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