1.A,B are 2 different values of x between 0&180 which satisfies 6cosx+8sin=9.Find sin(a+B).
2.If tanx+tan(x+60)+Tan(x+120)=3, prove that {3tanx-(tanx)^3}/{1-3(tanx)^2}=1
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Trigonometry questions...
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Trigonometry questions...1.A,B are 2 different values of x between 0&180 which satisfies 6cosx+8sin=9.Find sin(a+B).
2.If tanx+tan(x+60)+Tan(x+120)=3, prove that {3tanx-(tanx)^3}/{1-3(tanx)^2}=1 razr[img height="60" width="60"]http://farm1.static.flickr.com/143/3737 ... 69.jpg?v=0[/img]
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