prob que

by **pkciit** » Thu Mar 13, 2008 9:51 pm

Q. if from a lottery of 25 tickets marked 1 to 25 ,four tickets are drawn,what is the probability that those marked 15 and 16 are among them? :?:

by **kauser** » Thu Mar 13, 2008 11:43 pm

I think this will be the answer , but some 1 pls confirm

P(A)= P(getting 15) P(B)= P(getting 16)

P(A n B)= PA.PB

1/25.1/25= 1/625 will be the answer.........

I am not sure if this is ryt

and are the cards drawn with or without replacement.

Some1 pls correct me if I am wrong.

by **pkciit** » Fri Mar 14, 2008 9:44 am

the ans. is 1/50
i am unable to solve this que someone plz give the solution :?:

by **pkciit** » Fri Mar 14, 2008 11:26 am

hey guys i think it will proceed like this.......... i got it

p(getting no 15)=4c1/25c1=4/25
p(getting no 16 given no 15)=3c1/24c1=3/24=1/8
p(getting both 15 & 16)=p(16/15)* p(15)=4/25*1/8=1/50 :mrgreen:

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